A) 74.2
B) 75.6
C) 67.83
D) 78.7
Correct Answer: C
Solution :
We have, \[\frac{{{p}^{0}}-21.85}{21.85}=\frac{30\times 18}{90\times m}\], for I case .....(i) wt. of solvent \[=90+18=108gm\] \[\frac{{{p}^{0}}-22.15}{22.15}=\frac{30\times 18}{108\times m}\], for II case .....(ii) By eq. (1) \[p_{m}^{0}-21.85m=21.85\times 6=131.1\] By eq. (2) \[p_{m}^{0}-22.15m=22.15\times 5=110.75\] 0.30m = 20.35 \[m=\frac{20.35}{0.30}=67.83\]You need to login to perform this action.
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