A) \[8abc\le (a+b)(b+c)(c+a)\]
B) \[3abc\le {{a}^{3}}+{{b}^{3}}+{{c}^{3}}\]
C) \[6abc\le bc(b+c)+ca(c+a)+ab(a+b)\]
D) \[abc\le (a+b-c)(b+c-a)(c+a-b)\]
Correct Answer: D
Solution :
Trick: Let \[a=2,\,b=3,\,c=4\] and check with the options.
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