A) \[\frac{1}{2}\]
B) 2
C) 1
D) \[-\frac{1}{2}\]
Correct Answer: B
Solution :
\[\cos [\pi -(B+C)]=\cos B\cos C\] Þ \[-\cos (B+C)=\cos B\cos C\] Þ \[-[\cos B\cos C-\sin B\sin C]=\cos B\cos C\] Þ \[\sin B\sin C=2\cos B\cos C\] Þ \[\tan B\tan C=2\].You need to login to perform this action.
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