JEE Main & Advanced Physics Magnetic Effects of Current / करंट का चुंबकीय प्रभाव Question Bank Critical Thinking

  • question_answer
    A circular current carrying coil has a radius R. The distance from the centre of the coil on the axis where the magnetic induction will be \[\frac{1}{8}th\] to its value at the centre of the coil, is [MP PMT 1997]

    A)            \[\frac{R}{\sqrt{3}}\]        

    B)            \[R\sqrt{3}\]

    C)            \[2\sqrt{3}\,R\]                   

    D)            \[\frac{2}{\sqrt{3}}R\]

    Correct Answer: B

    Solution :

                       \[\frac{{{B}_{centre}}}{{{B}_{axis}}}={{\left( 1+\frac{{{x}^{2}}}{{{R}^{2}}} \right)}^{3/2}},\]also \[{{B}_{axis}}=\frac{1}{8}{{B}_{centre}}\] \[\Rightarrow \frac{8}{1}={{\left( 1+\frac{{{x}^{2}}}{{{R}^{2}}} \right)}^{3/2}}\Rightarrow 2={{\left( 1+\frac{{{x}^{2}}}{{{R}^{2}}} \right)}^{1/2}}\] \[\Rightarrow 4=1+\frac{{{x}^{2}}}{{{R}^{2}}}\Rightarrow 3=\frac{{{x}^{2}}}{{{R}^{2}}}\Rightarrow {{x}^{2}}=3{{R}^{2}}\]\[\Rightarrow x=\sqrt{3}R\]


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