A) 313/293
B) \[\sqrt{(313/293)}\]
C) 1/2
D) 2
Correct Answer: A
Solution :
Average kinetic energy \[\propto \] (T Kelvin) (Factor)\[\frac{K.{{E}_{2}}}{K.{{E}_{1}}}=\frac{{{T}_{2}}}{{{T}_{1}}}=\frac{40+273}{20+273}\] \[=\frac{313}{293}\]You need to login to perform this action.
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