A) \[MgL\]
B) \[MgL/3\]
C) \[MgL/9\]
D) \[MgL/18\]
Correct Answer: D
Solution :
\[W=\frac{MgL}{2{{n}^{2}}}=\frac{MgL}{2{{(3)}^{2}}}=\frac{MgL}{18}\] (n = 3 given)You need to login to perform this action.
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