A) 18.8 mm
B) 9.2 mm
C) 7.4 cm
D) 4.5 cm
Correct Answer: D
Solution :
V = V0(1 + g Dq) Þ Change in volume \[V-{{V}_{0}}=\Delta V=A.\Delta l={{V}_{0}}\gamma \Delta \theta \] Þ Dl = \[\frac{{{V}_{0}}.\Delta \theta }{A}\] = \[\frac{{{10}^{-6}}\times 18\times {{10}^{-5}}\times (100-0)}{0.004\times {{10}^{-4}}}\] = 45 × 10?3 m = 4.5 cm
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