A) \[qb\,B/m\]
B) \[q(b-a)B/m\]
C) \[qa\,B/m\]
D) \[q(b+a)B/2m\]
Correct Answer: B
Solution :
In the figure, the z-axis points out of the paper, and the magnetic field is directed into the paper, existing in the region between PQ and RS. The particle moves in a circular path of radius r in the magnetic field. It can just enter the region x > b for \[r\ge (b-a)\] Now, \[r=\frac{mv}{qB}\ge (b-a)\] or \[v\ge \frac{q(b-a)B}{m}\] Þ \[{{\nu }_{\min }}=\frac{q(b-a)B}{m}\]You need to login to perform this action.
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