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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Critical Thinking

  • question_answer
    \[p{{K}_{a}}\] values of two acids A and B are 4 and 5. The strengths of these two acids are related as     [KCET 2001]

    A)                 Acid A is 10 times stronger than acids B

    B)                 Strength of acid A: strength a of acid \[B=4:5\]

    C)                 The strengths of the two acids can not be compared

    D)                 Acid B is 10 times stronger than acid A                

    Correct Answer: A

    Solution :

               \[p{{K}_{a}}\] of acid \[A=4\] ; \[p{{K}_{a}}\]of acid \[B=5\]                    We know that \[p{{K}_{a}}=-\log \,\,{{K}_{a}}\]                    \ Acid A \[{{K}_{a}}={{10}^{-4}}\]                    Acid B \[{{K}_{a}}={{10}^{-5}}\]                                 Hence A is ten times stronger than that of B.


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