A) Zero
B) One
C) Two
D) Infinite
Correct Answer: C
Solution :
Given equation \[{{a}^{2}}-2a\sin x+1=0\] \[\therefore \] \[a=\frac{2\sin x\pm \sqrt{4{{\sin }^{2}}x-4}}{2}\] \[=\sin x\pm \sqrt{-(1-{{\sin }^{2}}x)}\] \[a=\sin x\pm i\cos x\] If \[x=\frac{\pi }{2}\]Þ \[a=1,\]\[x={{270}^{o}}\]Þ \[a=-1\].You need to login to perform this action.
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