A) \[{{M}^{-3}}{{L}^{-2}}{{T}^{-4}}{{A}^{-1}}\]
B) \[M{{L}^{-2}}\]
C) \[{{M}^{-3}}{{L}^{-2}}{{T}^{4}}{{A}^{4}}\]
D) \[{{M}^{-3}}{{L}^{-2}}{{T}^{8}}{{A}^{4}}\]
Correct Answer: D
Solution :
\[Y=\frac{X}{3{{Z}^{2}}}=\frac{{{M}^{-1}}{{L}^{-2}}{{T}^{4}}{{A}^{2}}}{{{[M{{T}^{-2}}{{A}^{-1}}]}^{2}}}=[{{M}^{-3}}{{L}^{-2}}{{T}^{8}}{{A}^{4}}]\]
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