A) 0.5%
B) 1.0%
C) 1.5%
D) 3.0%
Correct Answer: C
Solution :
In the problem orbital radius is increased by 1%. Time period of satellite \[T\propto {{r}^{3/2}}\] Percentage change in time period = \[\frac{3}{2}\](% change in orbital radius) = \[\frac{3}{2}(1%)=1.5%\]You need to login to perform this action.
You will be redirected in
3 sec