Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर
JEE Main & Advanced
Physics
Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर
Question Bank
Critical Thinking
question_answer
In the circuit as shown in the figure, the heat produced by 6 ohm resistance due to current flowing in it is 60 calorie per second. The heat generated across 3 ohm resistance per second will be [MP PET 1996]
A) 30 calorie
B) 60 calorie
C) 100 calorie
D) 120 calorie
Correct Answer:
D
Solution :
Resistance of upper branch \[{{R}_{1}}=2+3=5\,\Omega \] Resistance of lower branch \[{{R}_{2}}=4+6=10\,\Omega \] Hence \[\frac{{{i}_{1}}}{{{i}_{2}}}=\frac{{{R}_{2}}}{{{R}_{1}}}=\frac{10}{5}=2\] \[\frac{\text{Heat generated across 3 }\Omega \text{ (}{{\text{H}}_{\text{1}}})}{\text{Heat generated across 6 }\Omega \text{ (}{{\text{H}}_{\text{2}}})}\]\[=\frac{i_{1}^{2}\times 3}{i_{2}^{2}\times 6}=\frac{4}{2}=2\] \ Heat generated across 3 W = 120 cal/sec