2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Magnetism

JEE Main & Advanced Physics Magnetism Question Bank Critical Thinking

  • question_answer
    The dipole moment of each molecule of a paramagnetic gas is 1.5 ´ 10?23 amp ´ m2. The temperature of gas is 27oC and the number of molecules per unit volume in it is 2 ´ 1026 m?3. The maximum possible intensity of magnetisation in the gas will be

    A)            3 ´ 103 amp/m                    

    B)            4 ´ 10?3 amp/m

    C)            5 ´ 105 amp/m                    

    D)            6 ´ 10?4 amp/m

    Correct Answer: A

    Solution :

               \[I=\frac{M}{V}=\frac{\mu N}{V}=\frac{1.5\times {{10}^{-23}}\times 2\times {{10}^{26}}}{1}=3\times {{10}^{3}}Amp/m\]


You need to login to perform this action.
You will be redirected in 3 sec spinner