A) Zero
B) \[B\nu \pi {{R}^{2}}/2\] and M is at higher potential
C) \[\pi RBV\]and Q is at higher potential
D) 2RBV and Q is at higher potential
Correct Answer: D
Solution :
Rate of decrease of area of the semicircular ring \[-\frac{dA}{dt}=(2R)\ V\] According to Faraday's law of induction induced emf \[e=-\frac{d\varphi }{dt}=-\ B\frac{dA}{dt}=-\ B\ (2RV)\] The induced current in the ring must generate magnetic field in the upward direction. Thus Q is at higher potential.You need to login to perform this action.
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