A) Increases with time
B) Decreases with time
C) Does not vary with time
D) Passes through a maximum
Correct Answer: D
Solution :
Using k1, k2 etc, as different constants. \[{{I}_{1}}(t)={{k}_{1}}[1-{{e}^{-t/\tau }}],\ B(t)={{k}_{2}}{{I}_{1}}(t)\] \[{{I}_{2}}(t)={{k}_{3}}\frac{dB(t)}{dt}={{k}_{4}}{{e}^{-t/\tau }}\] \[\therefore {{I}_{2}}(t)\ B(t)={{k}_{5}}[1-{{e}^{-t/\tau }}][{{e}^{-t/\tau }}]\] This quantity is zero for \[t=0\] and \[t=\infty \] and positive for other value of t. It must, therefore, pass through a maximum.You need to login to perform this action.
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