A) 10 J
B) 20 J
C) 30 J
D) 40 J
Correct Answer: A
Solution :
\[H=\frac{{{V}^{2}}t}{R}\,and\ \ V=\frac{N({{B}_{2}}-{{B}_{1}})A\cos \theta }{t}\] \[V=\frac{1\times (1-2)\times 0.01\times \cos {{0}^{o}}}{{{10}^{-3}}}=10\ V\] So, \[H=\frac{{{(10)}^{2}}\times {{10}^{-3}}}{0.01}=10\ J\]You need to login to perform this action.
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