A) \[\frac{{{\mu }_{0}}\pi {{a}^{4}}}{8{{l}^{3}}}\]
B) \[\frac{{{\mu }_{0}}\pi {{a}^{4}}}{4{{l}^{3}}}\]
C) \[\frac{{{\mu }_{0}}\pi {{a}^{4}}}{6{{l}^{3}}}\]
D) \[\frac{{{\mu }_{0}}\pi {{a}^{4}}}{2{{l}^{3}}}\]
Correct Answer: D
Solution :
Magnetic field at the location of coil (2) produced due to coil (1) \[{{B}_{1}}=\frac{{{\mu }_{o}}}{4\pi }.\frac{2M}{{{l}^{3}}}\] Flux linked with coil (2) \[{{\varphi }_{2}}={{B}_{1}}{{A}_{2}}=\frac{{{\mu }_{o}}}{4\pi }\frac{2i\ (\pi {{a}^{2}})}{{{l}^{3}}}\times (\pi {{a}^{2}})\] Also \[{{\varphi }_{2}}=Mi\] \[\Rightarrow M=\frac{{{\mu }_{o}}\pi {{a}^{4}}}{2{{l}^{3}}}\]You need to login to perform this action.
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