A) \[BeF_{3}^{-}\]
B) \[OH_{3}^{+}\]
C) \[NH_{2}^{-}\]
D) \[N{{F}_{3}}\]
Correct Answer: A
Solution :
\[BeF_{3}^{-}\] does not show \[s{{p}^{3}}\]?hybridization because this compound is not formed.You need to login to perform this action.
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