A) \[C{{H}_{3}}-CH=C{{H}_{2}}\underset{O{{H}^{-}}}{\mathop{\xrightarrow{{{B}_{2}}{{H}_{6}}}}}\,\]
B) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}I\underset{P}{\mathop{\xrightarrow{HI}}}\,\]
C) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}Cl\xrightarrow{Na}\]
D) None of these
Correct Answer: A
Solution :
Hydroboration of alkenes followed by hydrolysis in basic medium yield alcohols and not the alkanes. \[R-CH=C{{H}_{2}}\xrightarrow{{{B}_{2}}{{H}_{6}}}{{(R-C{{H}_{2}}-C{{H}_{2}})}_{3}}-B\]\[\xrightarrow{O{{H}^{-}}}R-C{{H}_{2}}-C{{H}_{2}}OH\]
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