A) \[[{{M}^{0}}{{L}^{2}}{{T}^{0}}]\]
B) \[[{{M}^{1}}{{L}^{2}}{{T}^{1}}]\]
C) \[[{{M}^{1}}{{L}^{0}}{{T}^{-1}}]\]
D) \[[{{M}^{0}}{{L}^{2}}{{T}^{-1}}]\]
Correct Answer: A
Solution :
In given equation, \[\frac{\alpha z}{k\theta }\] should be dimensionless \[\therefore \]\[\alpha =\frac{k\theta }{z}\Rightarrow [\alpha ]=\frac{[M{{L}^{2}}{{T}^{-2}}{{K}^{-1}}\times K]}{[L]}=[ML{{T}^{-2}}]\]and \[P=\frac{\alpha }{ \beta }\Rightarrow [\beta ]=\left[ \frac{\alpha }{p} \right]=\frac{[ML{{T}^{-2}}]}{[M{{L}^{-1}}{{T}^{-2}}]}=[{{M}^{0}}{{L}^{2}}{{T}^{0}}]\].
You need to login to perform this action.
You will be redirected in
3 sec
