A) 12 min
B) 64 min
C) 8 min
D) 32 min
Correct Answer: B
Solution :
If 40 ml \[{{O}_{2}}\] will diffuse in t min. then. \[{{r}_{{{O}_{2}}}}=\frac{40}{t}\] \[{{r}_{H}}=\frac{50}{20}\] Þ \[{{r}_{O}}={{r}_{H}}\,2\sqrt[{}]{\frac{{{M}_{{{H}_{2}}}}}{{{M}_{{{O}_{2}}}}}}=\frac{50}{20}\sqrt{\frac{2}{32}}=\frac{50}{20}.\frac{1}{4}\] \[\frac{40}{t}=\frac{50}{80}\therefore t=\frac{40\times 80}{50}=60\] min.
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