A) 1/3
B) 1/2
C) 1/4
D) 1/5
Correct Answer: B
Solution :
\[F=\frac{Gm(M-m)}{{{r}^{2}}}\] For maximum force \[\frac{dF}{dm}=0\] Þ\[\frac{d}{dm}\left( \frac{GmM}{{{r}^{2}}}-\frac{G{{m}^{2}}}{{{r}^{2}}} \right)=0\] Þ\[M-2m=0\,\Rightarrow \,\frac{m}{M}=\frac{1}{2}\]You need to login to perform this action.
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