JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Critical Thinking

  • question_answer
    A non-conducting solid sphere of radius \[R\] is uniformly charged. The magnitude of the electric field due to the sphere at a distance \[r\] from its centre                                                                          [IIT-JEE 1998; DPMT 2000]

    A)                    Increases as \[r\] increases for \[r<R\]

    B)                    Decreases as \[r\] increases for \[0<r<\infty \]

    C)                    Decreases as \[r\] increases for \[R<r<\infty \]

    D)                    Is discontinuous at \[r=R\]

    Correct Answer: A , C

    Solution :

     For non-conducting solid sphere \[{{E}_{in}}\propto r\]                    and \[{{E}_{out}}\propto \frac{1}{{{r}^{2}}}\] i.e. for r < R; E increases as r increases and for R < r < ¥; E decreases as r increases

    Solution :

     For non-conducting solid sphere \[{{E}_{in}}\propto r\]                    and \[{{E}_{out}}\propto \frac{1}{{{r}^{2}}}\] i.e. for r < R; E increases as r increases and for R < r < ¥; E decreases as r increases


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