A) 120 ohm
B) 50 ohm
C) 60 ohm
D) 90 ohm
Correct Answer: C
Solution :
\[{{i}_{L}}=\frac{90}{30}=3\ A,\] \[{{i}_{C}}=\frac{90}{20}=4.5\ A\] Net current through circuit \[i={{i}_{C}}-{{i}_{L}}\ =1.5\ A\] \[\therefore Z=\frac{V}{i}=\frac{90}{1.5}=60\Omega \]You need to login to perform this action.
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