A) Carbonium ion
B) Alkoxy ion
C) Alkyl hydrogen sulphate
D) None of these
Correct Answer: A
Solution :
\[-\underset{\underset{H}{\mathop{|}}\,}{\overset{|}{\mathop{C}}}\,\,\,\,\,\,-\underset{\underset{\,\,\,\,OH}{\mathop{|}}\,}{\overset{|}{\mathop{C}}}\,-\] \[-\underset{\underset{\underset{\begin{smallmatrix} \text{Protonated} \\ \,\,\,\,\,\text{alcohol} \end{smallmatrix}}{\mathop{H}}\,}{\mathop{|}}\,}{\overset{|}{\mathop{C}}}\,-\underset{\underset{{}^{+}O{{H}_{2}}}{\mathop{|}}\,}{\overset{|}{\mathop{C}}}\,-\] In all cases intermediate is carbonium ion, and there may be 1, 2-hydride or 1, 2-methyl shift to form more stable carbonium ion.You need to login to perform this action.
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