A) + 2
B) ? 1
C) ? 2
D) Zero
Correct Answer: A
Solution :
\[\int_{\,-\infty }^{\,0}{-\overrightarrow{E}\,\cdot \overrightarrow{dl}}\]= potential at centre of non-conducting ring \[=\frac{1}{4\pi {{\varepsilon }_{0}}}\times \frac{q}{r}=\frac{9\times {{10}^{9}}\times 1.11\times {{10}^{-10}}}{0.5}=2\,volt\]You need to login to perform this action.
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