A) \[E=\frac{3}{4}\frac{m{{v}^{2}}}{qa}\]
B) Rate of work done by electric field at P is \[\frac{3}{4}\frac{m{{v}^{3}}}{a}\]
C) Rate of work done by electric field at P is zero
D) Rate of work done by both the fields at Q is zero
Correct Answer: B
Solution :
Kinetic energy of the particle at point \[P=\frac{1}{2}m{{v}^{2}}\]You need to login to perform this action.
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