A) 0o
B) 30o
C) 45o
D) 90o
Correct Answer: C
Solution :
In vertical plane perpendicular to magnetic meridian. \[T=2\pi \sqrt{\frac{I}{M{{B}_{V}}}}\] ..... (i) In horizontal plane \[T=2\pi \sqrt{\frac{I}{M{{B}_{H}}}}\] ..... (ii) Equation (i) and (ii) gives \[{{B}_{V}}={{B}_{H}}\] Hence by using \[\tan \varphi =\frac{{{B}_{V}}}{{{B}_{H}}}\Rightarrow \tan \varphi =1\Rightarrow \varphi ={{45}^{o}}\]You need to login to perform this action.
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