A) Halved
B) The same
C) Doubled
D) Quadrupled
Correct Answer: B
Solution :
Power \[P=\frac{{{e}^{2}}}{R};\] hence \[e=-\left( \frac{d\varphi }{dt} \right)\] where \[\varphi =NBA\] \[\therefore e=-\ NA\left( \frac{dB}{dt} \right)\] Also \[R\propto \frac{l}{{{r}^{2}}}\] Where R = resistance, r = radius, l = Length \[\therefore P\propto \frac{{{N}^{2}}{{r}^{2}}}{l}\] \[\Rightarrow \frac{{{P}_{1}}}{{{P}_{2}}}=1\]You need to login to perform this action.
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