JEE Main & Advanced Physics Alternating Current / प्रत्यावर्ती धारा Question Bank Critical Thinking

  • question_answer
    In a certain circuit current changes with time according to \[i=2\sqrt{t}.\] r.m.s. value of current between \[t=2\] to \[t=4s\] will be

    A)            \[3A\]                                     

    B)            \[3\sqrt{3}A\]

    C)            \[2\sqrt{3}A\]                      

    D)            \[(2-\sqrt{2})A\]

    Correct Answer: C

    Solution :

    \[\overline{{{i}^{2}}}=\frac{\int_{{}}^{{}}{{{i}^{2}}dt}}{\int_{{}}^{{}}{dt}}=\frac{\int_{2}^{4}{(4t)}dt}{\int_{2}^{4}{dt}}=\frac{4\int_{2}^{4}{t\ dt}}{2}\]  \[=2\left[ \frac{{{t}^{2}}}{2} \right]_{2}^{4}=\left[ {{t}^{2}} \right]_{2}^{4}=12\]            \[\Rightarrow {{i}_{rms}}=\sqrt{\overline{{{i}^{2}}}}=\sqrt{12}=2\sqrt{3}\ A\]


You need to login to perform this action.
You will be redirected in 3 sec spinner