A) 10
B) 8
C) 6
D) 4
Correct Answer: C
Solution :
\[\frac{1}{\lambda }=R\left[ \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right]\] \[\Rightarrow \frac{1}{970.6\times {{10}^{-10}}}=1.097\times {{10}^{7}}\left[ \frac{1}{{{1}^{2}}}-\frac{1}{n_{2}^{2}} \right]\]\[\Rightarrow {{n}_{2}}=4\] \[\therefore \]Number of emission lines \[N=\frac{n(n-1)}{2}=\frac{4\times 3}{2}=6\]
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