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JEE Main & Advanced Physics Semiconducting Devices Question Bank Critical Thinking

  • question_answer
    The junction diode in the following circuit requires a minimum current of 1 mA to be above the knee point (0.7 V) of its I-V characteristic curve. The voltage across the diode is independent of current above the knee point. If VB  = 5 V, then the maximum value of R so that the voltage is above the knee point, will be

    A)            4.3 kW                                     

    B)            860 kW

    C)            4.3 W                                       

    D)            860 W

    Correct Answer: A

    Solution :

                       At knee point voltage across the diode is 0.7V. Hence voltage across resistance R is 5 ? 0.7 = 4.3 V. Þ using V = iR Þ 4.3 = 1 ´ 10?3 ´ R  Þ R = 4.3 kW.


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