A) ab
B) abe
C) \[\frac{e}{ab}\]
D) \[\frac{ab}{e}\]
Correct Answer: B
Solution :
\[b\sqrt{{{a}^{2}}-{{b}^{2}}}\]if \[a>b;a\sqrt{{{b}^{2}}-{{a}^{2}}}\]if \[P\] Area of \[P{{F}_{1}}{{F}_{2}}=\frac{1}{2}({{F}_{1}}{{F}_{2}})\times PL\] \[=\frac{1}{2}(2ac)\times y=ae.\frac{b}{a}\sqrt{{{a}^{2}}-{{x}^{2}}}\] \[A=eb\sqrt{{{a}^{2}}-{{x}^{2}}}\], which is maximum when\[x=0\]. Thus the maximum value of A is abe.You need to login to perform this action.
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