A) 2-butene
B) Propene
C) 1-phenylpropene
D) 2-methyl-2-butene
Correct Answer: A
Solution :
2-butene \[\underset{\text{(cis)}}{\mathop{\begin{matrix} \begin{matrix} \, \\ C{{H}_{3}}-\underset{|}{\mathop{C}}\,=\underset{|}{\mathop{C}}\,-{{C}_{6}}{{H}_{5}} \\ \end{matrix} \\ H\,\,\,\,\,H \\ \end{matrix}}}\,\] and \[\underset{\text{(Trans)}}{\mathop{C{{H}_{3}}-\underset{H\,\,}{\mathop{\underset{/\,\,}{\mathop{C}}\,}}\,=\overset{\,\,\,H}{\mathop{\overset{\,\,\,\,/\,\,}{\mathop{C}}\,}}\,-{{C}_{6}}{{H}_{5}}}}\,\]You need to login to perform this action.
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