A) \[6.0\times {{10}^{27}}C\]
B) \[2.67\times {{10}^{7}}C\]
C) \[6\times {{10}^{23}}C\]
D) \[1.67\times {{10}^{23}}C\]
Correct Answer: B
Solution :
\[Q=ne\]; where n = number of moles\[~\times \text{6}.0\text{2}\times \text{1}{{0}^{\text{23}}}\times \text{1}0\] Þ \[Q=\frac{500}{18}\times 6.02\times {{10}^{23}}\times 10\times 1.6\times {{10}^{-19}}=2.67\times {{10}^{7}}C\]
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