A) \[{{m}^{3}}\] only
B) \[d{{m}^{3}}\] only
C) \[c{{m}^{3}}\] only
D) Any one of them
Correct Answer: D
Solution :
\[w=2.303\,RT\,\log \frac{{{V}_{2}}}{{{V}_{1}}}.\]As it involves the ratio \[\frac{{{V}_{2}}}{{{V}_{1}}}\], volume can be used in any units. (R should be in joules).You need to login to perform this action.
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