A) ?0.3024 kJ
B) 0.3024 kJ
C) 2.567 kJ
D) ?0.0076 kJ
Correct Answer: A
Solution :
\[{{C}_{2}}{{H}_{2}}(g)+{{H}_{2}}(g)\to {{C}_{2}}{{H}_{4}}(g)\] \[\Delta ng=1-2=-1\]; \[\Delta H=-0.31\,KJ\,mo{{l}^{-1}}\] \[P=1.5\,atm\], \[\Delta V=-50\,mL=-0.050L\] \[\Delta H=\Delta E+P\Delta V\] \[-0.31=\Delta E-0.0076\]; \[\Delta E=-0.3024\,KJ\]You need to login to perform this action.
You will be redirected in
3 sec