A) \[3.42\times {{10}^{-6}}\]
B) \[3.42\times {{10}^{-8}}\]
C) \[1.00\times {{10}^{-14}}\]
D) \[2.00\times {{10}^{-16}}\]
Correct Answer: D
Solution :
\[\alpha =1.9\times {{10}^{-9}}\]; \[C=\frac{1000}{18}\] \[K=\frac{[{{H}^{+}}]\,\,[O{{H}^{-}}]}{({{H}_{2}}O)}=C{{\alpha }^{2}}\] \[=1.9\times {{10}^{-9}}\times 1.9\times {{10}^{-9}}\times \frac{1000}{18}\]\[=2.0\times {{10}^{-16}}\].You need to login to perform this action.
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