A) 4.50
B) 8.00
C) 7.00
D) 10.00
Correct Answer: B
Solution :
\[pH=pKa+\log \frac{[Salt]}{[Acid]}\] \[pH=pKa\] \[Ka=0.1\times {{({{10}^{-3.5}})}^{2}}=0.1\times {{10}^{-7}}={{10}^{-8}}\] Þ \[pH=8\]You need to login to perform this action.
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