A) \[{{10}^{-12}}M\]
B) \[{{10}^{-11}}M\]
C) \[{{10}^{-9}}M\]
D) \[{{10}^{-2}}M\]
Correct Answer: A
Solution :
\[[{{H}^{+}}]=C\times \alpha =0.1\times 0.1={{10}^{-2}}M\] pH = 2; pOH = 12 ; \[[O{{H}^{-}}]={{10}^{-12}}M\].You need to login to perform this action.
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