A) \[5\pi /4\]
B) \[\pi /2\]
C) \[3\pi /4\]
D) \[\pi /4\]
Correct Answer: C
Solution :
Given that arg zw =\[\pi \] .....(i) \[\bar{z}+i\bar{\omega }=0\Rightarrow \bar{z}=-i\bar{\omega }\]\[\Rightarrow z=i\omega \]\[\Rightarrow \omega =-iz\] From (i), arg\[(-i{{z}^{2}})=\pi \] \[arg\ (-i)+2arg(z)=\pi \] ; \[\frac{-\pi }{2}+2\ arg(z)=\pi \] \[2\,arg\,(z)=\frac{3\pi }{2}\]; \[a\,rg(z)=\frac{3\pi }{4}\]You need to login to perform this action.
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