A) \[\frac{1}{4\pi {{\varepsilon }_{0}}}A\gamma _{0}^{3}\]
B) \[4\pi {{\varepsilon }_{0}}A\gamma _{0}^{3}\]
C) \[\frac{4\pi {{\varepsilon }_{0}}A}{{{\gamma }_{0}}}\]
D) \[\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{A}{\gamma _{0}^{3}}\]
Correct Answer: B
Solution :
Flux linked with the given sphere \[\varphi =\frac{Q}{{{\varepsilon }_{o}}};\] where Q = Charge enclosed by the sphere. Hence Q = feo = (EA)eo Þ Q = 4p (go)2 ´ Agoeo = 4peoAgo3.You need to login to perform this action.
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