A) \[10\,\,A{{m}^{2}}\]
B) \[15\,\,A{{m}^{2}}\]
C) \[20\,\,A{{m}^{2}}\]
D) \[25\,\,A{{m}^{2}}\]
Correct Answer: D
Solution :
We have, \[B={{\mu }_{0}}H+{{\mu }_{0}}I\] or \[I=\frac{B-{{\mu }_{0}}H}{{{\mu }_{0}}}\] or \[I=\frac{\mu H-{{\mu }_{0}}H}{{{\mu }_{0}}}=\left( \frac{\mu }{{{\mu }_{0}}}-1 \right)H\] \[I=({{\mu }_{r}}-1)H\] For a solenoid of n-turns per unit length and current i H = ni \[\therefore \ \ I=({{\mu }_{r}}-1)ni\]\[=(1000-1)\times 500\times 0.5\] \[I=2.5\times {{10}^{5}}A{{m}^{-1}}\] \[\therefore \ \ \]Magnetic moment M=IV \[M=2.5\times {{10}^{5}}\times {{10}^{-4}}\]= 25 Am2
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