A) End A, \[3\times {{10}^{-3}}\,mV\]
B) End A, 3 mV
C) End B, \[3\times {{10}^{-3}}\,mV\]
D) End B, 3 mV
Correct Answer: B
Solution :
Induced potential difference between two ends \[=Blv={{B}_{H}}lv\] \[=3\times {{10}^{-5}}\times 2\times 50=30\times {{10}^{-3}}volt=3\,millivolt\] By Fleming's right hand rule, end A becomes positively charged.You need to login to perform this action.
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