A) \[-2730\,kJ\]
B) \[-462\,kJ\]
C) \[-1365\,kJ\]
D) \[+\,2730\,kJ\]
Correct Answer: B
Solution :
\[2Al+\frac{3}{2}{{O}_{2}}\to A{{l}_{2}}{{O}_{3}},\,\,\,\Delta H=-1596\,kJ\] ?..(i) \[2Cr+\frac{3}{2}{{O}_{2}}\to C{{r}_{2}}{{O}_{3}},\,\,\,\Delta H=-1134\,kJ\] ?..(ii) By (i) ? (ii) \[2Al+C{{r}_{2}}{{O}_{3}}\to 2Cr+A{{l}_{2}}{{O}_{3}},\,\,\,\Delta H=-462\,kJ\].You need to login to perform this action.
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