A) \[\frac{{{\nu }_{1}}-{{\nu }_{2}}}{k-1}\]
B) \[\frac{k{{\nu }_{1}}-{{\nu }_{2}}}{k-1}\]
C) \[\frac{k{{\nu }_{2}}-{{\nu }_{1}}}{k-1}\]
D) \[\frac{{{\nu }_{2}}-{{\nu }_{1}}}{k}\]
Correct Answer: B
Solution :
By using \[h\nu -h{{\nu }_{0}}={{K}_{\max }}\] \[\Rightarrow h({{\nu }_{1}}-{{\nu }_{0}})={{K}_{1}}\] ?.(i) And \[h({{\nu }_{2}}-{{\nu }_{0}})={{K}_{2}}\] ?.(ii) \[\Rightarrow \frac{{{\nu }_{1}}-{{\nu }_{0}}}{{{\nu }_{2}}-{{\nu }_{0}}}=\frac{{{K}_{1}}}{{{K}_{2}}}=\frac{1}{K}\], Hence \[{{\nu }_{0}}=\frac{K{{\nu }_{1}}-{{\nu }_{2}}}{K-1}\].You need to login to perform this action.
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