A) Propanal and mesitylene
B) Propanone and mesityl oxide
C) Propanone and 2,6-dimethyl -2, 5-heptadien-4-one
D) Propanone and mesitylene oxide
Correct Answer: C
Solution :
The compound A with formula \[{{C}_{3}}{{H}_{6}}O\] gives iodoform test, it is propanone forms a compound B having carbon atoms three times, the number of carbon atoms in propanone, it is 2, 6-dimethyl-2, 5-heptadien-4-one.You need to login to perform this action.
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