A) \[\frac{5}{4}d\]
B) \[\frac{4}{5}d\]
C) \[d\]
D) \[\frac{d}{5}\]
Correct Answer: A
Solution :
Weight of cylinder = upthrust due to both liquids \[V\times D\times g=\left( \frac{A}{5}\,\times \frac{3}{4}L \right)\times d\times g+\left( \frac{A}{5}\times \frac{L}{4} \right)\times 2d\times g\] Þ\[\left( \frac{A}{5}\times L \right)\,\times D\times g=\frac{A\times L\times d\times g}{4}\]Þ\[\frac{D}{5}=\frac{d}{4}\] \[\therefore \ D=\frac{5}{4}d\]
You need to login to perform this action.
You will be redirected in
3 sec
