A) 0.1256 sec
B) 0.1356 sec
C) 0.1456 sec
D) 0.1556 sec
Correct Answer: A
Solution :
By drawing free body diagram of object during the downward motion at extreme position, for equilibrium of mass \[mg-R=mA\] (A = Acceleration) For critical condition R = 0 so mg = mA \[\Rightarrow mg=ma{{\omega }^{2}}\] \[\Rightarrow \omega =\sqrt{g/a}=\sqrt{\frac{9.8}{3.92\times {{10}^{-3}}}}=50\] \[\Rightarrow T=\frac{2\pi }{\omega }=\frac{2\pi }{50}=0.1256sec\]You need to login to perform this action.
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